Solve the system by substitution 5x+3y=8 3x+y=8

First you'd have to eliminate one of the variables, so which I used y. So to get rid of y, you need to multiply the whole equation, 3x+y=8, by 3. Which then you get 9x+3y=24.

On the second equation, it's stays the same. 5x+3y=8, except you chane the value of the number, so if it's positive change it to negative and vice versa.

So now you have -5x-3y=-8 and 9x+3y=24.

9x + 3y =24

-5x - 3y = 8

if you combine the terms, you'll see y is removed from the equation 3y-3y=0.

You're left with 4x=16, which x is 4.

Now you can substitute 4 for x to find y. Just use one of the equations to do this to, try 3x+y=8.

3(4)+y=8.

12+y=8

y=-4.

If you need the answer to be in a point form, it's (4,-4)

so, converting firstly the mixed fractions to improper fractions and then "adding".