Correct answers only ! i cannot retake which statement best reflects the solution(s) of the equation?

but x = 1 does not satisfy the Equation

So, The answer is :

There is only one solution : x = 8

The solution x = 1 is an extraneous solution

x = 8

              x = 1 is an extraneous solution

Step-by-step explanation:

- x + 3 = 0

RESTRICTIONS: 3x + 1 ≥ 0   →   x ≥  (because square roots cannot be less than zero/negative)

- x + 3 = 0

             +x  -3 +x  -3

             = x - 3

          = (x - 3)²

3x + 1                 = x² - 6x + 9

-3x   -1                          -3x   -1

                      0  = x² - 9x + 8

                      0  = (x - 1)(x - 8)

                 0 = x - 1         0 = x - 8

                +1      +1         +8     +8

                  1 = x              8 = x      both solutions are ≥

Check:  

x = 1: - (1) + 3 = 0

         2 - 1 + 3 = 0

                    4 = 0

                   FALSE   so x = 1 is NOT a valid solution

x = 8: - (8) + 3 = 0

         5 - 8 + 3 = 0

                    0 = 0

                    TRUE   so x = 8 is a valid solution

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer