Arectangle has a perimeter of 18 inches. a new rectangle is formed by doubling the with w in tripling the length l as shown the new rectangle has a perimeter p of 46 inches

Let Original rectangle has length L and Width W.

Perimeter = 18 inches

→2(L+W)=18

Dividing both sides by 2,we get

L+W=9  (1)

Now, new rectangle is formed by doubling the width Wand tripling the length L.

New length=3 L

New Breadth=2W

New perimeter=46 inches

→2(3 L+2W)=46

Dividing both sides by 2, we get

3L+ 2W=23

→L=9-W  [Using 1]

Substituting in (2), we get

3(9-W)+2W=23

27-3W+W=23

W=27-23

W=4

and L=9-4=5 inches

So, Original rectangle has Length=5 inches, and Width=4 inches

what is the original number? you forgot to add it.