Find the range of possible values of x. a. 12 < x < 13 b. 3 < x < 12 c. 0 < x < 13 d. 0 < x < 8

0 < x < 13

Step-by-step explanation:

In the given figure, we have two triangles JIG and JHG.

The sides IJ from the triangle JIG and side GH  from triangle JHG are congruent.

Also, since JG is a common side in both of the triangles so they are also equal.

The angle between these two congruent sides (JG and GH) is 35° which is smaller than the angle between the other congruent sides JG and IJ i.e. 59°.

Therefore, the side JH is also smaller than IG which is 13 so:

x < 13

and JH must be greater than zero, so we can write it as:

0 < x < 13

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i hope this : )