What is the equation of a line that is parallel to −x+3y=6 and passes through the point (3, 5) ? enter your answer in the box.

x - 3y = -12

Step-by-step explanation:

First find the slope by converting the given equation to slope-intercept form.

-x + 3y = 6

3y = x + 6

y = 1/3x + 2

- meaning that the slope = 1/3.

Y - y1 = m(x - x1)  where m = 1/3 and (x1, y1) = (3, 5):-

y - 5 = 1/3(x - 3)   Multiply each tern by 3:-

3y - 15 = x - 3

x - 3y = -12   is the required equation

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