Between which pair of consecutive integers does √111 lie
a: 20 and 22
b: 10 and 11
c: 4 and 5
d: 5 and 6

The given lie between 10 and 11

B is correct

Step-by-step explanation:

We need to find pair of number in which lie between them.

Let given number lie between two integer x and y

Thus,

Taking square both sides

As we assumed x and y are integers.

We will choose two number across 111 those are perfect square.

Taking square root all sides

Hence, The given lie between 10 and 11.

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1