Different question jake is skipping stones onto a pond. each time he flings a stone in, he counts the number of times it skips over the water. the number of skips he recorded for each stone were 3, 2, 1, 3, 2, 5, 4, 1, 3, 3, 4, 1, 5, 4, and 2. which measure should jake use to calculate the difference of the highest and the lowest number of skips?

Range

Step-by-step explanation:

We are given the following data set for the number of skips every time Jake skipped a stone onto a pond:

3, 2, 1, 3, 2, 5, 4, 1, 3, 3, 4, 1, 5, 4, 2

It is a good idea to arrange the data set into ascending order just to be more clear about it:

1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5

Jake should find the range by calculating the difference of the highest and the lowest number of skips

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0