Which is an equation in point slope form of the line that passes through the points (7 -8) and (-4,6)

slope = (y2-y1)/(x2-x1)

= (6--8)/(-4-7)

=14/-11

point slope form

y-y1=m(x-x1)

y--8 = -14/11(x-7)

y+8 = -14/11 (x-7)

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation: