Find two consecutive integers whose product is 50

n, n+1 - two consecutive integers

n(n + 1) = 50     use distributive property

n² + n = 50     subtract 50 from both sides

n² + n - 50 = 0

ax² + bx + c =0

if b² - 4ac > 0 then we have two solutions:

[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a

if b² - 4ac = 0 then we have one solution -b/2a

if  b² - 4ac < 0 then no real solution

n² + n - 50 = 0

a = 1, b = 1, c = -50

b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions

√(b² - 4ac) = √(201) - it's the irrational number

There are no two consecutive integers whose product is 50.

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )