Find the equation in slope-intercept form, of the line passing through the points (1,3) and (-1,2)

The equation of the line would be y = .5x + 2.5

Step-by-step explanation:

In order to find this, we must first find the slope of the equation.

m (slope) = (y2 - y1)/(x2 - x1)

m = (2 - 3)/(-1 - 1)

m = -1/-2

m = .5

Now that we have the slope, we can use either point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 3 = .5(x - 1)

y - 3 = .5x - .5

y = .5x + 2.5

your answer would be 10x - 1

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°