Find the zeros of y = x^2 - 4x - 9 by completing the square. a. x = -2 ± √13 b. x = 2 ± √13 c. x = ±3 d. x = 3 ± √13

Try this option:

x²-4x-9=x²-4x+4-13=(x-2)²-13=(x-2)²-√(13)²

it means, the answer is

last one.

step-by-step explanation:

last one.

generally speaking, the others follow some sort of pattern that correlates to either linear (looks like a straight line) or sinusoidal (looks like an s).

the last one is just a random cloud of points that doesn't correlate to any particular known order.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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