If the sum of five consecutive even integers is 290, what is the smallest of the five integers?

So let n be the smallest number. To have consecutive even integers each number goes up by 2 so n, n+2, n+4, n+6, n+8.

Therefore, n+n+2+n+4+n+6+n+8=290

5n+20=290

5n=270

n=54

y do u put "subscirbe to ence" on a app for ppl who need with their work?

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.