3x-2y=6 y=3/2x-3 find the slope, x-intercept, and y-intercept for both equations.

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have 3x - 2y = 6       subtract 3x from both sides

-2y = -3x + 6      divide both sides by -2

y = 3/2 x - 3

slope: m = 3/2

y-intercept: b = -3

x-intercept for y = 0. Substitute:

3/2 x - 3 = 0      add 3 to both sides

3/2 x = 3       multiply both sides by 2/3

x = 2

y = 3/2 x - 3 it's the same function like first function.

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

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step-by-step explanation: