Find the center, vertices, and foci of the ellipse with equation x squared divided by 36 plus y squared divided by 100 = 1

General equation is

Where (h,k) is the center

From the given equation h=0  and k=0

So center is (0,0)

compare the given equation with general equation

b^2 = 36  so b= 6

a^2 = 100 so a = 10

Vertices are (h, k+a) and (h, k-a)

We know h=0  , k=0  and a= 10

Vertices are (0,-10)  and (0,10)

Foci are (h, k+c)  and (h,k-c)

We know h=0  , k=0  and c=8

Foci are (0,-8)  and (0,8)

can you give me more detail on this! ?

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)