Find the coordinates of point b on line ac such that ab is 1/3 of ac. i have tried everything, i would really appreciate someone's input on this, you.

The coordinates of B are (3, -1).

Step-by-step explanation:

Here's one possible, straightforward way in which you can identify the point B:

Notice that in going straight up from A to C, y increases by 12 units.  

Going to the right from A to C, x increses by 3 units.

The x-coordinate of B is (x-coordinate of A) + (1/3)(increase in x going from A to B).  Thus, the x-coord. of B is (2 + [1/3][3]) = 2 + 1 = 3.

The y-coord. of B is (y-coord. of A + 1/3(increase in y going from A to B), or -5 + (1/3)[12]) = -5 + 4 = -1.

So the coordinates of B are (3, -1).

7

step-by-step explanation:

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0