What are the excluded values for 1/x-x/9=0. explain how you get you answer

Excluded values are the values that make the denominator 0

Denominator 0 is undefined so we exclude the values that makes the denominator 0

LCD is 9x

Multiply the first fraction by 9 and second fraction by x

We have 9x in the denominator

When x=0 the denominator becomes 0

so excluded value is x=0

im guessing (23,14). hope this : )