What are the domain restrictions of the expression g^2+7g+12/g^2−2g−24 ? select each correct answer. g≠−6 g≠4 g≠3 g≠6 g≠−3 g≠−4 asap

(-infinity, -4) ∪ (-4, 6) ∪ (6, +infinity)

Step-by-step explanation:

Any domain restrictions here stem only from division by zero.  Thus, we take the denominator, g^2−2g−24, and purposely set it to 0, and solve for g:

g^2−2g−24 = 0 => (g-6)(g+4) = 0.  Solving for g, g=6 and g= -4.

This function is defined for all values of g other than 6 and -4.  We could also write the domain as follows: (-infinity, -4) ∪ (-4, 6) ∪ (6, +infinity).

step-by-step explanation:

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so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

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