For which equations below is x = –3 a possible solution? check all that apply. |x| = 3 |x| = –3 |–x| = 3 |–x| = –3 –|x| = –3 –|x| = 3

The correct options are A, C and E.

Step-by-step explanation

If a absolution equation is defined as

Then the solutions of the equation are x=a and x=-a.

A.

So,x=-3 is a solution of this equation.

B.

This equation has no solution because the value of |x| can no

be negative.

C.

So,x=-3 is a solution of this equation.

D.

This equation has no solution because the value of |-x| can no

be negative.

E.

Divide both sides by -1.

So,x=-3 is a solution of this equation.

F.

Divide both sides by -1.

This equation has no solution because the value of |x| can not be negative.

Therefore the correct options are A, C and E.

the function makes a strait line horizontally with no x intercept but a y intercept at 9.

answer:   c ?

step-by-step explanation: