Calculate the distance between (2 + 2i) and (6 + 5i).

u − v = 〈s − a, t − b〉

u − v = √(s − a)2 + (t − b)2

EXAMPLE 1 Finding the Distance Between Points

in the Complex Plane

Find the distance between the points 2 + 3i and 5 − 2i in the complex plane.

Solution

Let a + bi = 2 + 3i and s + ti = 5 − 2i. The difference between the complex

numbers is

(5 − 2i) − (2 + 3i) = (5 − 2) + (−2 − 3)i = 3 − 5i.

The distance is

d = √32 + (−5)2 = √34 ≈ 5.83 units

Step-by-step explanation:

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: