3x^2-n-4y^2=(3x-y)(x+4y),n=? need asap f.11xy g.-11xy h.13xy j.-13xy

n = -11xy, so the answer is G.

Step-by-step explanation:

3x^2−n−4y^2=(3x−y)(x+4y)

Step 1: Add -3x^2 to both sides.

3x^2−4y^2−n+−3x^2=3x^2+11xy−4y^2+−3x^2

−4y^2−n=11xy−4y^2

Step 2: Add 4y^2 to both sides.

−4y^2−n+4y^2=11xy−4y^2+4y^2

−n=11xy

Step 3: Divide both sides by -1.

n=−11xy

10 b/c 5*2 =10

step-by-step explanation: