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Mathematics, 04.07.2019 09:30 ndh64

Select from the drop-down menus to correctly complete the proof. to prove that 2βˆšβ‹…7 is irrational, assume the product is rational and set it equal to ab , where b is not equal to 0. isolating the radical gives 2√=a7b . the right side of the equation is (irrational, rational). because the left side of the equation is (irrational, rational), this is a contradiction. therefore, the assumption is wrong, and the product is (rational, irrational).

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Select from the drop-down menus to correctly complete the proof. to prove that 2βˆšβ‹…7 is irrational,...
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