Select from the drop-down menus to correctly complete the proof. to prove that 2√⋅7 is irrational, assume the product is rational and set it equal to a/b , where b is not equal to 0. isolating the radical gives 2√= a/7b. the right side of the equation is(irrational, rational). because the left side of the equation is(irrational, rational), this is a contradiction. therefore, the assumption is wrong, and the product is(rational, irrational).

We need to prove 2*√7 is an irrational number.

Steps:

1) To prove that 2√7 is an irrational, assume the product is rational and set it equal to a/b , where b is not equal to 0.

2)  Isolating the radical gives 2= a/√7b.

3) The right side of the equation is irrational.

4)  Because the left side of the equation is rational, this is a contradiction.

5) Therefore, the assumption is wrong, and the product is irrational.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.