What is the complete factorization of the polynomial function over the set of complex numbers? f(x)=x3−5x2+4x−20 enter your answer in the box.

f(x) = (x-5)(x+2i)(x-2i)

Step-by-step explanation:

Given that

f(x)=x3−5x2+4x−20

Grouping first two terms together and second set together we have

f(x) = x^2(x-5)+4(x-5)

= (x^2+4)(x-5)

These are the factors without complex numbers of f(x)

Equate each factor  to 0 to get

x-5 =0 or x^2+4=0

x =5 or x = square root of -4

i.e. x=5 or x = 2i or x =-2i (since square root of negative number is imaginary)

Factorisation is

f(x) = (x-5)(x+2i)(x-2i)

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

i think the answer is b.

step-by-step explanation:

not 100% sure though.