The degree of the polynomial function f(x) is 3 the roots of the equation f(x) = 0 are -2, 0, and 3 which graph could be the graph of f(x)?

If the roots of the equation f(x) = 0 are -2, 0, and 3  and the degree of the polynomial function f(x) is 3, then the polynomial has a form

The x-intercepts of the graph of this polynomial function are:

These points are x-intercepts of the graph of the last function (option D).

The last graph at bottom right.

Step-by-step explanation:

We are given the degree of the polynomial function f(x) to be 3; and

the roots of the equation f(x) to be 0 and -2, 0, and 3.

So we will put these values in the polynomial function of degree 3 to get:

According to this, the x - intercepts of this function on the graph will be:

(0, 0)

(-2, 0)

(3, 0)

So we will look for a graph which intercepts the x-axis at these points.

Therefore, the last graph at the bottom right satisfies the conditions and is the graph of f(x).

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3