Will give brainliest! and extra points.

How far did the frog jump? the answer is one of the solutions of the quadratic equation

because that's where the frogs height is 0 (y=0) feet.

Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.

The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825

So, the correct answer is (a) 30 ft far and 3.83 high.

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

copyright potato 2019.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.