Line passing through (4,-1) and (3,-2)

If you are trying to find the equation for a line passing through those points, first we subtract the points.

(4,-1)

-(3,-2)

(1, 1)

Then we find out what our slope (m) would be by Rise (y) over Run (x)

1/1 = 1

y = mx + b is our equation for lines.  M is the slope.  Now we solve for B, by plugging one of our points into the equation.

-1 = 1(4) + b

-1 = 4 + b

-5 = b

Now that we have B, we have our full equation.  y = x -5.  Hope this helped!

-TTL

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )