Regina has a bag of marbles that contains 3 blue marbles, 4 red marbles, and 5 yellow marbles. she draws one marble, then replaces it, and draws one more. there are possible outcomes. the probability the first drawn marble will be blue is . the probability the second marble drawn will be yellow is . so, p(blue, then yellow) =

Possible outcomes=12

Step-by-step explanation:

We can see these two events are independent as Regina replaced marble after drawing one marble.

We can find possible outcomes by adding number of blue, red and yellow marbles.

Let us find probability of getting a blue marble on first draw.

Now we will find probability of getting yellow marble.

We can find probability of getting a blue marble and then yellow marble by multiplying both probabilities.

Therefore, probability of getting a blue marble and then yellow marble is .

The probability the first drawn marble will be blue is .

The probability the second marble drawn will be yellow is .

Step-by-step explanation:

From the given information, it is clear that

Number of blue marbles = 3

Number of red marbles = 4

Number of yellow marbles = 5

Total number of marbles = 3+4+5 = 12

The probability the first drawn marble will be blue is:

She draws one marble, then replaces it, and draws one more. It means total number of marbles remains same.

The probability the second marble drawn will be yellow is:

We need to find the value of P(blue, then yellow).

Therefore, the required probability is .

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

table 3 represents a direct variation function. : )