Choose the equation below that represents the line that passes through the point (-2, -1) and has a slope of 5

point slope form  y-y1=m(x-x1)

                               y-(-1) =5(x-(-2))

                           y+1 = 5(x+2)

to get it into slope intercept form

distribute

y+1 = 5x+10

subtract 1 from each side

y = 5x+9

y = 5x + 9

Step-by-step explanation:

The equation of a line in its standard form can be written as:

y = mx + c

where  y is the y coordinate,

m is the gradient of the line,

x is the x coordinate; and

c is the y intercept.

We will substitute the values of x and y coordinates and the slope to find the y intercept.

y = mx + c

-1 = (5) (-2) + c

c = 9

Therefore, the equation of the line which passes through the point (-2, -1) and has a slope of 5 will be y = 5x + 9.

3x^3-x^2+6x-9