Raj tried to solve the system below. 9x-y=15 2x+8y=28 raj’s work 9x - y = 15 2x + 8y(15 + 9x) = 28 9(-46/37) - y = 15 -y = 15 - 9x 2x + 120 + 72x = 28 -414/37 - y = 15 y = -15 + 9x 74x + 120 = 28 y = 969/37 74x = -92 x = -46/37 what error did raj make? a) rag forgot to multiply the value of x by 9 when solving for the value of y. b) when raj solved for the value of x, he subtracted 120 from both sides. c) raj forgot the negative when substituting –15 + 9x for y. d) raj found the value of –y instead of y.

Option C) Raj forgot the negative when substituting -15+9x for y.

Solution:

(1) 9x-y=15

(2) 2x+8y=28

Isolating y in the first equation. Subtracting 9x both sides of the equation:

(1) 9x-y-9x=15-9x

Subtracting:

(1) -y=15-9x

Multiplying both sides of the equation by -1:

(1) (-1)(-y)=(-1)(15-9x)

(1) y=-15+9x

Then Raj found the value of y. It's not option D.

Substitutng y by -15+9x in the second equation:

(2) 2x+8(-15+9x)=28

Then option C) is the Raj forgot the negative when substituting -15+9x for y.

Eliminating the parentheses applying the distributive property in the multiplication:

(2) 2x-120+72x=28

Adding similar terms:

(2) 74x-120=28

Solving for x. Adding 120 both sides of the equation:

(2) 74x-120+120=28+120

Adding:

(2) 74x=148

Dividing both sides of the equation by 74:

(2) 74x/74=148/74

Dividing:

(2) x=2

Solving for y: Replacing x by 2 in the first equation:

(1) y=-15+9x

(1) y=-15+9(2)

Multiplying:

(1) y=-15+18

Subtracting:

(1) y=3  

c

Step-by-step explanation:

edg 2020

600,000,000,000, or 6e14

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb