He length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle. a. 21 in. b. 22 in. c. 32 in. d. 16 in.

The formula of a perimeter of rectangle:

P = 2(w + l)

We have l = 12 in and P = 56 in.

Substitute:

2(w + 12) = 56      use distributive property

(2)(w) + (2)(12) = 56

2w + 24 = 56       subtract 24 from both sides

2w = 32      divide both sides by 2

w = 16

only 10/60 isn't equivalent

hope this : )

10 you would take 50/ .2

step-by-step explanation: