5: use the points (20,10) and (70,110) and the slope formula to generate the point-slope equation of the trend line6: apply the properties of equality to rewrite the equation you found in question 5 in slope-intercept and standard form

(5) use the points (20,10) and (70,110)

slope =

(20,10)  is (x1,y1)  and (70,110)  is (x2,y2)

slope =

so slope = 2

the point-slope equation of the trend line is

m is the slope. m=2, x1= 20 and y1= 10

The point slope equation is y - 10 = 2(x - 20)

(6) rewrite the equation you found in question 5 in slope-intercept and standard form

y - 10 = 2(x - 20)

To find slope intercept form we need to get y alone,

distribute 2 inside the parenthesis

y - 10 = 2x - 40

Add 10 on both sides

Slope intercept form is y = 2 x - 30

Standard form is Ax + By = C

y = 2x - 30

Subtract 2x from both sides

-2 x + y = -30

i really dont know

step-by-step explanation: