Jean's scores on the first three of four 100-point tests were 82, 86, and 91. what score must she receive on the fourth test to have an average of at least 87 points for all the tests

The total for an average to be 87 would have be 87 x the number of tests or 87 x 4 = 348.

Let's see the total for her previous 3: 82 + 86 + 91 = 259

The 4th one needs to take her from 259 to 348.

348 - 259 = 89. she has 89 'to go" to get that 87 average.

She requires an 89 to achieve an 87 test average.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

stethere all not eveanp-by-step explanation: