For 99 pts and brainliest the vertices of kite defg are (5, 5), (8, 2), (5, -4), and (2, 2), respectively. prove that the diagonals of kite defg are perpendicular lines.

See below

Step-by-step explanation:

Vector argument

Vector DF is (5, -4) - (5, 5) = (0, -9).

Vector EG is (2, 2) - (8, 2) = (-6, 0).

The dot-product of these two vector is (0, -9)•(-6, 0) = 0·(-6) + (-9)·0 = 0.

When the dot-product of two vectors is zero, those vectors are at right-angles to each other. Therefore diagaonal DF ⊥ diagonal EG.

Alternate argument

The x-coordinates of points D and F are the same, so diagonal DF is a vertical line. The y-coordinates of points E and G are the same, so diagonal EG is a horizontal line. Vertical lines are perpendicular to horizontal lines, so DF ⊥ EG.

right

step-by-step explanation:

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}