Which ordered pair is the vertex of y=|x+5|-1

Y = I x + 5 I -1

f(-x) : I x + 5 I - 1

I- x + 5 I - 1

- f(x) = - I x + 5 I + 1

- ( I x + 5 I ) - ( -1 )

- I x + 5 I  + 1

f(-x) ≠ f(x) therefore I x + 5 I -1 is not an even function .

f(-x) ≠ - f(x) therefore I x + 5 I - 1 is not an odd function.

Neither even nor odd

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hope this helps!