Need quick according to an x/y table, when x = –3, y = 21; when x = 4, y = –28; and when x = 5, y = –35. type the constant of variation, k. just type a number (possibly a fraction, with a slash). if this is not direct variation, type the word no.

According to an x/y table, when x = –3, y = 21; when x = 4, y = –28; and when x = 5, y = –35.

when x = –3, y = 21

If it is a direct variation then it satisfies y = kx

Lets plug in -3  for x  and 21  for y and find out k

y = kx

21= k (-3)

Divide by -3 on both sides

So k = -7

Lets check whether k = -7 for the other two set of values

when x = 4, y = –28,

-7 times 4 = -28

when x = 5, y = –35

-7 times 5 = -35

k =-7 satisfies all the set of values

So constant of variation k = -7

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign