Write an equation to represent the following: three consecutive integers add up to 11 more than the smallest.

Step-by-step explanation:

First we have to assume the smallest integer.

Let,

the smallest integer is  x

So, the other two integers are-

x+1  and   x+2

Now,  

the sum of these 3 integers is greater than smallest integer by  11

So, we get

x+(x+1)+(x+2) =x+11

This is the required equation.

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4