What is the solution of the equation when solved over the complex numbers? x^2+27=0 !

x = ± 3i√3

given x² + 27 = 0 (subtract 27 from both sides )

x² = - 27 ( take the square root of both sides )

x = ± = ± √(9 × 3 × -1 ) ← (i = √-1 )

  = ± (√9 × √3  ×√-1 ) = ±3i√3

answer:

probably the same as it is today since you did not eat the corn dogs yet

step-by-step explanation:

it goes right