Amath teacher gave her students two tests. on the first test, 80% of the class passed the test, but only 30% of the class passed both tests. what is the probability that a student passes the second test, given that they passed the first one? 0.256 0.375 0.500 0.625

0.375 is answer

Step-by-step explanation:

Given that the  math teacher gave her students two tests. On the first test, 80% of the class passed the test.  But only 30% of the class passed both tests.

Let A - the students pass I test

B = students pass second test

Then P(A) = 80%=0.8 and P(AB) = 30% =0.30

Required probability =probability that a student passes the second test, given that they passed the first one

= P(B/A) = P(AB)/P(A)

= 0.30/0.80

=3/8

=0.375

Right answer is 0.375

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.

the answer is

d.

5.3066 m2

step-by-step explanation: