Adistribution is normal with mu= 12.0 and sigma= 3.0. if i select one individual at random what is the probability that said individual is between 9.2 and 17.6

the probability between 9.2 and 17.6 is, 0.79237.

Step-by-step explanation:  

It is given that distribution is normal.Also given the value of  

and .

Use :

Now,  

Calculate First

then we put the value of x =9.2 in the z transform,i.e,

Using the standard Normal table of N(0,1); we get

⇒

Similarly, for

put the value of x =17.6 in the z-transform we get;

By the Normal Table N(0,1); we get

⇒  

Then, the probability between 9.2 and 17.6 i.e,

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

bull

step-by-step explanation: