Find equation of line in slope-intercept from having a slope 2/3 and passing through the point (-6, 4)

For this case we have the following data:

Slope,

By definition, the equation of the slope-intercept form is given by:

We must find the cut point b, for this we substitute the given point and the slope in the equation:

Thus, the equation is given by:

Now, we look for the points of intersection with the x and y axes respectively:

Point of intersection with the y axis:

We do and substitute in the equation found:

Thus, the point of intersection with the y-axis is (0,8).

Point of intersection with the x axis:

We make and substitute in the equation found:

Clear x:

Thus, the point of intersection with the x-axis is (-12.0).

See attached image

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47