Acube has an edge length of 5 inches. you triple the side lengths. how many times greater is the volume of the new cube?

Edge length of the side of a cube = 5 inches
Then
Volume of the cube = (side)^3
                                = (5)^3
                                 = 125 inches ^3
So the volume of the actual cube is 125 inches^3
Now after the side lengths are triple, then
New edge length of each side = 3 * 5 inches
                                                = 15 inches
Then
New volume of the cube = (New side)^3
                                        = (15)^3
                                         = 3375 inches^3
Then the volume of the new  cube is 3375 inches^3
So
The number of times the volume of the new cube is greater = 3375/125
                                                                                                 = 27
So the volume of the new cube is 27 times greater than the old cube.

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4