1/a+1/b=c solve for b how would i do this

a cheap way to go about it is, let's do away with the denominators, and we'll do so by simply multiplying both sides by the the LCD of all fractions, in this case, that'd be "ab", so we multiply both sides by "ab".

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )