About 12% of the population of a large country is hopelessly romantic. if two people are randomly selected, what is the probability both are hopelessly romantic/ what is the probability least one is hopelessly romantic?

Probabilities are used to determine the chances of an event

The given parameters are:

--- proportion that are hopelessly romantic

--- the selected sample

(a) The probability that both are hopelessly romantic

This is calculated as:

So, we have:

Express as percentage

Hence, the probability that both are hopelessly romantic is 0.0144

(b) The probability that at least one is hopelessly romantic

First, calculate the probability that none are hopelessly romantic

This is calculated as:

So, we have:

Express as percentage

Using the complement rule, the probability that at least 1 is hopelessly romantic

Hence, the probability that at least 1 is hopelessly romantic is 0.2256

Read more about probabilities at:

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If two people are randomly selected, then the probability both are hopelessly romantic=0.0144

If two people are randomly selected, then the probability at least one is hopelessly romantic =0.2256

Step-by-step explanation:

Binomial probability distribution formula :-

, where P(x) is the probability of success in x trials , n is the total number of trials and p is the probability of success.

Given : The probability of population of a large country is hopelessly romantic =0.12

If two people are randomly selected, then the probability both are hopelessly romantic :-

If two people are randomly selected, then the probability at least one is hopelessly romantic:-

282 6/7 cm^2

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.