Mr. chong has 1,440 pages of scrap paper. he ins tead wants to make packets of 40 pages each but forgets to check if that will be enough for his 37 students. will there be enough packets per student? if not how much more scrap pap er does he need? solution?

1440/40 = 36

 there are only 36 packets

he will need 1 more packet

Each packet contains 40 pages

so he will need 40 more pieces of scrap paper

No. He has enough for 36 students, not for 37.

He needs another 40 pages.

Step-by-step explanation:

1440/40 = 36

He has enough paper to make exactly 36 packets of 40 pages each.

He needs another 40 pages.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.