What is the sum of all values of m that satisfy 2m (squared) -16m+8=0?

So for this, we will be completing the square to solve for m. Firstly, subtract 8 on both sides:

Next, divide both sides by 2:

Next, we want to make the left side of the equation a perfect square. To find the constant of this perfect square, divide the m coefficient by 2, then square the quotient. In this case:

-8 ÷ 2 = -4, (-4)² = 16

Add 16 to both sides of the equation:

Next, factor the left side:

Next, square root both sides of the equation:

Next, add 4 to both sides of the equation:

Now, while this is your answer, you can further simplify the radical using the product rule of radicals:

√12 = √4 × √3 = 2√3.

In exact form, your answer is

In approximate form, your answers are (rounded to the hundreths)

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones

1/4 is the answer if i recall correctly.