Farmer ed has7500 meters of fencing, and wants to enclose a rectangular plot that borders on a river. if farmer ed does not fence the side along the river, what is the largest area that can be enclosed?

7,031,250 m^2

Step-by-step explanation:

We know that:

Area of a rectangle = length x width

Also, since the rectangular plot shares a border with a river so Farmer Ed only needs to fence rest of the three sides therefore, we can write it as:

F = x + 2y

7500 = x + 2y

Solving this equation for x, we get:

x = 7500 - 2y --- (i)

Now substitute this value of x in the Area of rectangle:

Area = (7500 - 2y) * y

Area = -2y^2 + 7500y --- (ii)

The coefficient of -2 means that the largest area will be at:

-7500 / [2 (-2) ] = 1875 so y = 1875

So substituting this value of y in the equation (i) we get:

x = 7500 - 2(1875)

x = 7,031,250 m^2

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x