Determine which statements are true about the extrema of the graphed to fourth degree polynomial. select all that apply.

Refer answer below

Step-by-step explanation:

Given is a graph in the interval (-infinity, infinity).

From the graph we observe that it is continuous graph.

The curve is decreasing for x <-2 and increases for (-2,1) and again decreases from (1,3) then increases from (3,infinity)

Hence f'(x) >0 for (-2,1) and (3,infinity)

f'(x) <0 for (-infty, -2) and (1,3)

From the above we find that f'(x) =0 for x=-2,1,and 3

Extreme points are -2,1 and 3

Absolute and local minima at x=-2, y=-9.67

Local maxima at (1,6.08) and again

local minima at (3,0.75)

Absolute maxima  lies at infinity

 Option 4. overall minimum in (-2.9.67)

Step-by-step explanation:

A global maximum point (x0, f (x0)) is defined as the point at which f (x0) is the maximum value of the function. That is, there is no value in the domain of f (x) other than x0 where f (x) is greater than f (x0)

A global minimum point (x0, f (x0)) is defined as the point at which f (x0) is the smallest value of the function. That is, there is no value in the domain of f (x) other than x0 where f (x) is less than f (x0)

Based on that deficion we must look for the point where f (x) has the lowest value.

That point is (-2.9.67)

Therefore that is the overall minimum of the function.

Although the function has a maximum in (1.6.08), the function keeps growing for x> 4, that means that there is a point where the function is bigger than in x = 1.

Therefore this is not a local maximum.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times