In a contest to guess the number of jelly beans in a jar, alice guessed 25; betty, 18; clare,23; dotty,19; edith,24; and fran,17. two were off by 2, two were off by 3, two were off by 4. how many beans are in the jar?

There are 21 jelly beans in the jar.

Step-by-step explanation:

Suppose, the number of jelly beans in the jar is  

Two were off by 2, two were off by 3, two were off by 4. That means, the six guessed number will be:  

Given that, Alice guessed 25; Betty, 18; Clare, 23; Dotty, 19; Edith, 24; and Fran, 17.

So, the sum of all six guessed number will be:  

Thus, the equation will be..........

So, the number of jelly beans in the jar is 21.

look a the sides they are perpendicular

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2