Araindrop drops from a window ledge of a building. the window ledge is 80 feet above the ground. how long does it take before the drop passes by another window ledge that is 16 feet above the ground?

It takes 2 seconds before the drop passes through another window ledge that is 16 ft above the ground.

Step-by-step explanation:

The formula to find time is

Here the drop falls from a window which at a height of 80 ft.

Hence the initial velocity = 0 = u

Now when it passes through a widow at a height of 16 ft, it has covered a distance of = 80-16 = 64 ft = d

It is falling under the gravity so its acceleration = g = 9.8 m/s² = 32 ft /s²

Substituting the values in the formula we get

Dividing both sides by 16 we get

Taking square root on both sides we get

no not all of them.

step-by-step explanation:

some of them have a square base.

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).