△mno is rotated about point a to △ m ′ n ′ o ′ . which statements are true about the pre-image and image? select each correct answer. - ∠nom≅ ∠n'o'm - mn ≅ m'n> ' < this one has a line on top of the letters. -the image is the same size but a different shape than the pre-image. -the image is the same shape but a different size than the pre-image.

△MNO is rotated about point N to △ M ′ N ′ O ′ .

⇒As you know that during Rotation the shape rotates by a certain angle, without changing it's shape and size.The two shapes i.e image and pre-image are congruent to each other.

Out of the options given :

- ∠NOM≅ ∠N'O'M  [Two triangles are congruent]

- MN ≅ M'N  [Sides are congruent]

is correct.

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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